RE: Parsing file without execution

["Joshua Jensen" <jjensen@...>]

Hi! 
I'd like to load a script file without executing it at the same time. In
lua_dobuffer(), the script is explicitely executed using lua_call(): 
    LUA_API int lua_dobuffer (lua_State *L, const char *buff, size_t
size, const char *name) { 
      int status = parse_buffer(L, buff, size, name); 
      if (status == 0)  /* parse OK? */ 
        status = lua_call(L, 0, LUA_MULTRET);  /* call main */ 
      return status; 
    } 
There seems to be no function like lua_parsefile() or lua_loadfile()
which I could use. 
Do I have to add this function myself, or is there a way only load/parse
a file without modifying lua ? 
-Markus- 
----------------

There is in Lua 4.1.

Josh