Re: run a lua page (cgilua) in command line

[Robert Raschke <rrlua@...>]

I run a little program to allow some templating using the cgilua
stuff.  The function script() takes a filename and returns the cgi'ed
contents as a string. You'll have to decide what to do about errors.

Robby

scripter.lua:
--[[
	This is a shim layer around the scripting technology of CGILua.

	The idea is to use the CGILua pretty much as a black box,
	knowing only about the includehtml() function, which does the
	<% %> magic.

	To get this to work we set ourselves up as a Server API (SAPI,
	part of the CGI Lua setup), which assembles the result of the
	script as a string.  The original way is to write out the
	result to standard output, which is not useful for us.
        Additionally we put errors into the log.
]]

local SCRIPTER_RESULT = ""

SAPI = {
	Response = {
		-- Headers, nuthin'
		contenttype = function (s) return end,
		redirect = function (s) return end,
		header = function (h, v) return end,
		-- Contents
		write = function (s) SCRIPTER_RESULT = SCRIPTER_RESULT .. (s or "") end,
		errorlog = function (s) do_something_about_the_error(s) end,
	},
	Request = {
		-- We do not deal with Input POST data
		getpostdata = function (n) return nil end,
		-- Input general information
		servervariable = function (n) return os.getenv(n) or "UNSET" end,
	},
}
require"cgilua"

cgilua.seterrorhandler(function (msg) do_something_about_the_error(msg) end)
cgilua.seterroroutput(function (msg) SAPI.Response.errorlog(msg) end)

put = SAPI.Response.write

function file_exists(file_name)
	local file = io.open(file_name)
	if file then
		file:close()
	end
	return file ~= nil
end

function script(name)
	assert( file_exists(name), "Cannot read template '" .. name .. "': No such file.")
	SCRIPTER_RESULT = ""
	cgilua.includehtml(name)
	return SCRIPTER_RESULT
end