Re: vararg is empty when loading certain chunks?

[Chris <coderight@...>]

Thanks for the quick reply!  Yes, that seems to work and does what I need.

Is there a reason why this is not the default way of assembling the
files?  It seems like being able to pass arguments is a good thing but
maybe it has complications I don't understand.

Thanks again!

CR


On 1/18/07, Rici Lake <lua@ricilake.net> wrote:
> On 18-Jan-07, at 6:53 PM, Chris wrote:
>
> > What happened to the arguments in the first case?
>
> They got lost because ... is not a variable.
>
> When you compile multiple files, luac assembles them as though
> you'd written:
>
> (function(...)
>    <file1>
> end)()
>
> (function(...)
>    <file2>
> end)()
>
> return (function(...)
>    <filen>
> end)()
>
> (except there are no line ends so the line numbers are preserved.)
>
> What you (probably) want is the following conversion:
>
> (function(...)<file1> end)(...)
> (function(...)<file2> end)(...)
> return (function(...)<filen> end)(...)
>
> Since that's not very pretty to do in Lua (it's hard to retain the
> correct line numbers while doing the combination), you could try the
> following patch to luac.c:
>
> --- ../../lua-5.1.1/src/luac.c  Fri Jun  2 12:37:11 2006
> +++ luac.c      Thu Jan 18 21:01:30 2007
> @@ -126,8 +126,9 @@
>     Proto* f=luaF_newproto(L);
>     setptvalue2s(L,L->top,f); incr_top(L);
>     f->source=luaS_newliteral(L,"=(" PROGNAME ")");
> -  f->maxstacksize=1;
> -  pc=2*n+1;
> +  f->maxstacksize=2;
> +  f->is_vararg = VARARG_ISVARARG;
> +  pc=3*n+1;
>     f->code=luaM_newvector(L,pc,Instruction);
>     f->sizecode=pc;
>     f->p=luaM_newvector(L,n,Proto*);
> @@ -137,7 +138,8 @@
>     {
>      f->p[i]=toproto(L,i-n-1);
>      f->code[pc++]=CREATE_ABx(OP_CLOSURE,0,i);
> -   f->code[pc++]=CREATE_ABC(OP_CALL,0,1,1);
> +   f->code[pc++]=CREATE_ABC(OP_VARARG,1,0,0);
> +   f->code[pc++]=CREATE_ABC(OP_CALL,0,0,1);
>     }
>     f->code[pc++]=CREATE_ABC(OP_RETURN,0,1,0);
>     return f;