I am completely new to Lua so please bare with me as I learn. I am
tring to make a simple test application that just lets me embed lua
into a C++ application. I have been reading the "Programming in Lua"
book online and I just followed the example exactly as written. I am
using Lua v5.1.1, Windows XP-SP2, and MinGW to compile my application.
I am including the lua source right in my project and every time I run
my application I get this error:
PANIC: unprotected error in call to Lua API (no calling environment)
I have tracked it down to the line:
luaopen_io(L);
If I comment it out I can use the interpreter as I would expect.
Here is the source for main.cpp
int main( int argc, char* argv[] )
{
char buff[256];
int error;
lua_State *L = lua_open(); /* opens Lua */
luaopen_base(L); /* opens the basic library */
luaopen_table(L); /* opens the table library */
luaopen_io(L); /* opens the I/O library */
luaopen_string(L); /* opens the string lib. */
luaopen_math(L); /* opens the math lib. */
while (fgets(buff, sizeof(buff), stdin) != NULL)
{
error = luaL_loadbuffer(L, buff, strlen(buff), "line") ||
lua_pcall(L, 0, 0, 0);
if (error)
{
fprintf(stderr, "%s", lua_tostring(L, -1));
lua_pop(L, 1); /* pop error message from the stack */
}
}
lua_close(L);
return 0;
}
Any ideas?
--
Regards,
Ryan
RJP Computing