RE: NEWBIE Question: LUA wait() function?

[gary ng <garyng2000@...>]

can you do os.execute() ? if yes, that may be the only
non-busy way as you can use some 'sleep' utility
programs.

--- Rolf <rb@san.rr.com> wrote:

> Thanks for all the responses. I think that I forgot
> to mention that I am
> running windows (XP);
> 
> 1. I tried sleep() and os.sleep, but it didn't work.
> 
> 2. I don't think that I can add any libraries
> because LUA is somehow
> built-in into the EccoExt executable (LUA is not
> separately installed).
> 
> 3. I tried the suggested:
> function wait(seconds)
>    local start = os.time()
>    repeat until os.time() > start + seconds
> end
> 
> for i=1,10 do
>    print(i)
>    wait(7)
> end
> 
> However, the CPU is going at close to 100% (as also
> mentioned) so that is
> not a viable option.
> 
> 4. I also tried:
> for i=1,10 do
>   print(i)
>   if os.execute("/bin/sleep 7") ~~= 0 then break end
> end
> 
> However, after the first print(i), the cmd window
> opened and closed and the
> loop stopped.
> 
> So in summary, I guess that there is no way to pause
> for a time without
> having the CPU close to 100%...?
> 
> p.s. I do not have a print command, but I am using
> msgbox(i) to check the
> "wait()" function.
>  
> 
> -----Original Message-----
> From: lua-bounces@bazar2.conectiva.com.br
> [mailto:lua-bounces@bazar2.conectiva.com.br] On
> Behalf Of Jorge Visca
> Sent: Tuesday, March 11, 2008 7:04 PM
> To: Lua list
> Subject: Re: NEWBIE Question: LUA wait() function?
> 
> For the ugly competition:
> 
> 
> for i=1,10 do
>   print(i)
>   if os.execute("/bin/sleep 7") ~~= 0 then break end
> end
> 
> 
> (the if ... break is for catching ctr-c while
> waiting)
> 
> :)
> 
> 



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