LOCALE ERROR - RE: how to compare 2 dates - NOW WITH TIME

[Diego - Red Baires <diego_redbaires@...>]

Hi guys, i still cannot apply the concept that Kein recommends.

Pls analize this results:

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myHour = os.time( { year="2008", month="01", day="01", hour="00", min="00" })

ts = math.fmod(myHour, 86400)

print (myHour .." - ".. ts)

myHour = os.time( { year="2009", month="01", day="00", hour="00", min="00" })

ts = math.fmod(myHour, 86400)

print (myHour .." - ".. ts)

----------

output: 

1199152800 - 7200

1230688800 - 7200

it continues to return "7200" if i change the year (it is what we expect) but it returns

different values to different months values. see this

----------

myHour = os.time( { year="2008", month="01", day="01", hour="00", min="00" })

ts = math.fmod(myHour, 86400)

print (myHour .." - ".. ts)

myHour = os.time( { year="2009", month="07", day="00", hour="00", min="00" })

ts = math.fmod(myHour, 86400)

print (myHour .." - ".. ts)

----------

output: 

199152800 - 7200

1246330800 - 10800

is it because of the locale ? 

do you have any example to set UTC locale ? (i coudnt find an example)

any idea ?

thanks

have a nice weekend,

diego

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