Re[4]: Function to parse filespec

[Bulat Ziganshin <bulat.ziganshin@...>]

Hello steve,

Wednesday, May 27, 2009, 3:28:06 PM, you wrote:

> Well, that's why I always use a loop myself!  Bear in mind that
> backslashes have another meaning in Unix paths.

my variant. much simpler, but doesn't handle alternative separators:

-- OS-dependent directory separator
DIR_SEPARATOR = "\\"

-- Return filename directory: c:\dir\file.ext -> c:\dir
function get_dir(filename)
  return (string.match (filename, "(.*)"..DIR_SEPARATOR..".+"))
end

-- Return filename without directory: c:\dir\file.ext -> file.ext
function drop_dir(filename)
  return (string.match (filename, ".*"..DIR_SEPARATOR.."(.+)"))
end

-- Return extension: file.ext -> ext
-- Filename passed shouldn't contain path!
function get_ext(filename)
  return string.match (filename, ".+[.](.*)") or ""
end

-- Drop extension: file.ext -> file
-- Filename passed shouldn't contain path!
function drop_ext(filename)
  return string.match (filename, "(.+)[.].*") or filename
end



-- 
Best regards,
 Bulat                            mailto:Bulat.Ziganshin@gmail.com